# 3 quarters, 1 dime, 2 nickels, and 1 penny

by bahzbsbaEVYHIGDYSVUW
(NY)

Howard has 3 quarters, 1 dime, 2 nickels, and 1 penny. Felicia has 1 quarter, 5 nickels, and 3 pennies. Together, the friends go to the store to buy colored pencils for school. Howard has enough money to buy 5 pencils but not enough for 6 pencils. Felicia has enough for 3 pencils but enough for 4. How much does a pencil cost.

### Comments for 3 quarters, 1 dime, 2 nickels, and 1 penny

 Jan 08, 2012 Word Problems by: Staff Question: by bahzbsbaEVYHIGDYSVUW (NY) Howard has 3 quarters, 1 dime, 2 nickels, and 1 penny. Felicia has 1 quarter, 5 nickels, and 3 pennies. Together, the friends go to the store to buy colored pencils for school. Howard has enough money to buy 5 pencils but not enough for 6 pencils. Felicia has enough for 3 pencils but enough for 4. How much does a pencil cost? Answer: Howard has 3 quarters, 1 dime, 2 nickels, and 1 penny. H = 3*(.25) + 1*(.10) + 2*(.05) + 1*(.01) H = 0.96 Felicia has 1 quarter, 5 nickels, and 3 pennies. F = 1*(.25) + 0*(.10) + 5*(.05) + 3*(.01) F = 0.53 Together, the friends go to the store to buy colored pencils for school. Howard has enough money to buy 5 pencils but not enough for 6 pencils. H = 0.96 5P ≤ H < 6P 5P ≤ 0.96 < 6P Solve each part of the inequality separately 5P ≤ 0.96 Divide each side of the inequality by 5 5P/5 ≤ 0.96/5 P*(5/5) ≤ 0.96/5 P*(1) ≤ 0.96/5 P ≤ 0.96/5 P ≤ 0.192 0.96 < 6P Divide each side of the inequality by 6 0.96/6 < 6P/6 0.96/6 < P*(6/6) 0.96/6 < P*(1) 0.96/6 < P 0.16 < P Harold: 0.16 < P ≤ 0.192 (for Harold to buy 5 pencils with \$0.96, but not have enough money to buy 6 pencils, the cost of each pencil must be greater than \$0.16 and less than or equal to \$0.192) Felicia has enough for 3 pencils but enough for 4. F = 0.53 3P ≤ F < 4P 3P ≤ 0.53 < 4P Solve each part of the inequality separately 3P ≤ 0.53 Divide each side of the inequality by 3 3P/3 ≤ 0.53/3 P*(3/3) ≤ 0.53/3 P*(1) ≤ 0.53/3 P ≤ 0.53/3 P ≤ 0.176667 0.53 < 4P Divide each side of the inequality by 4 0.53/4 < 4P/4 0.53/4 < P*(4/4) 0.53/4 < P*(1) 0.53/4 < P 0.1325 < P Felicia: 0.1325 < P ≤ 0.176667 (for Felicia to buy 3 pencils with \$0.53, but not have enough money to buy 4 pencils, the cost of each pencil must be greater than \$0.1325 and less than or equal to \$0.176667) How much does a pencil cost? Harold: 0.16 < P ≤ 0.192 Felicia: 0.1325 < P ≤ 0.176667 To meet the criteria for both people, pick the most restrictive price constraints: 0.16 < P ≤ 0.176667 >>>>>>>>>>>>>>>>>>>>>The FINAL ANSWER: the cost of each pencil must be greater than \$0.16 and less than or equal to \$0.176667 Thanks for writing. Staff www.solving-math-problems.com