# Add Fractions - Please help me to answer

by Sean
(Taguig City Philippines)

how to answer 2 1/4+3/8=????? and reduce it to lowest terms

### Comments for Add Fractions - Please help me to answer

 Aug 15, 2011 Add Fractions by: Staff The question: by Sean (Taguig City Philippines) how to answer 2 1/4+3/8=????? and reduce it to lowest terms The answer: 2 ¼ + 3/8=????? There are three widely used methods of adding these fractions: (1) add the whole numbers and the fractional components separately (2 + 0) + (¼ + 3/8); (2) convert the two numbers to their decimal equivalents, and then add the decimal equivalents (2.25 + 0.375); (3) convert any mixed numbers to improper fractions, and then add the fractions. I’m going to demonstrate the third method. Begin by converting the mixed number 2 ¼ into an improper fraction. This will make the addition of the two fractions much easier. (2*4 + 1 = 9, so the improper fraction will be 9/4) 2 ¼ + 3/8 = 9/4 + 3/8 Fractions cannot be added directly unless the denominators of both fractions are the same. Convert the fraction 9/4 to a fraction with a denominator of 8 (the same as the denominator of the fraction 3/8) To accomplish this, multiply the fraction 9/4 by another fraction: 2/2. Note that 2/2 = 1, so we are actually multiplying by 1. The decimal value of the fraction 9/4 will not change. = (9/4)*(2/2) + 3/8 = (9*2)/(4*2) + 3/8 = (18)/(8) + 3/8 = 18/8 + 3/8 Since the two fractions now have the same denominator, they can be easily added. (Remember, only the numerators are added. The denominator of 8 remains the same) = (18 + 3)/8 = 21/8 This fraction cannot be reduced, but it can be converted into a mixed number. = 21/8 To convert 21/8 to a mixed number, divide 21 by 8 = 21÷8 = 2, remainder 5 = 2 5/8 The final answer is: 2 5/8 (or 21/8 or 2.625) Check the answer with a calculator: 2 ¼ + 3/8 =????? = 2.25 + 0.375 = 2.625 Since 2.625 is the same answer obtained by converting 2 5/8 to its decimal equivalent, the answer of 2 5/8 is correct. Thanks for writing. Staff www.solving-math-problems.com

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