Age Word Problem - Math

by Wendy
(Elkhart)

a colonel spent 1/4 fo his life as a boy, 1/5 of his life as a young man, 1/3 of his life as a responsible adult, and 13 years on a pension. How old was he when he died?

Comments for Age Word Problem - Math

 Mar 29, 2012 Age Word Problem by: Staff Question: by Wendy (Elkhart) a colonel spent 1/4 of his life as a boy, 1/5 of his life as a young man, 1/3 of his life as a responsible adult, and 13 years on a pension. How old was he when he died? Answer: A = age at death years of life as a boy = (1/4)*A years of life as a young man = (1/5)*A years of life as a responsible adult = (1/3)*A years of life on a pension = 13 A = (years of life as a boy) + (years of life as a young man) + (years of life as a responsible adult) + (years of life on a pension) The equation which needs to be solved: A = (1/4)*A + (1/5)*A + (1/3)*A + 13 Solve for A A = (1/4)*A + (1/5)*A + (1/3)*A + 13 A = (15/60)*A + (12/60)*A + (20/60)*A + 13 A = (47/60)*A + 13 A - (47/60)*A = (47/60)*A + 13 - (47/60)*A A - (47/60)*A = (47/60)*A - (47/60)*A + 13 A - (47/60)*A = 0 + 13 A - (47/60)*A = 13 (13/60)*A = 13 (60/13)*(13/60)*A = (60/13)*13 (60/60)*(13/13)*A = (60/13)*13 (1)*(1)*A = (60/13)*13 A = (60/13)*13 A = (60)*(13/13) A = (60)*(1) A = 60 >>> the final answer: A = 60 years --------------------------------------------- Check the answer by substituting 60 for every “A” in the original equation. A = (1/4)*A + (1/5)*A + (1/3)*A + 13 60 = (1/4)*60 + (1/5)*60 + (1/3)*60 + 13 60 = 15 + 12 + 20 + 13 60 = 60, OK → A = 60 is a valid solution Thanks for writing. Staff www.solving-math-problems.com