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combining radicals and roots











































negative 6 times the 7th root of 2 minus 2 times the 7th root of 256

Comments for combining radicals and roots

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Jan 07, 2011
combining radicals and roots
by: Staff

The question:

negative 6 times the 7th root of 2 minus 2 times the 7th root of 256



The answer:

negative 6 times the 7th root of 2 minus 2 times the 7th root of 256


(-6)*[(2)^(1/7)] – (2)*[(256)^(1/7)]

(-6)*[(2)^(1/7)] – (2)*[(2*128)^(1/7)]


(-6)*[(2)^(1/7)] – (2)*[(2)^(1/7)]*[(128)^(1/7)]

Note: 128^(1/7) = 2

(-6)*[(2)^(1/7)] – (2)*[(2)^(1/7)]*2

(-6)*[(2)^(1/7)] – (4)*[(2)^(1/7)]

At this point you factor out the [(2)^(1/7)]

[(2)^(1/7)](-6-4)

[(2)^(1/7)](-10)

Final answer

(-10)*[(2)^(1/7)], which can be written as: negative 10 times the 7th root of 2




Thanks for writing.


Staff
www.solving-math-problems.com



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