# Estimating Cost using Proportions

Paul purchased 8 computers which cost him a total of \$6,016

Mary purchased 8 printers which cost her \$1,080.

Steve purchased 25 DVD movies which cost \$350

Sally purchased 34 CD’s which cost \$306.

41. How much would 3 computers, 4 printers, 15 DVD’s, and 18 CD’s cost ?

### Comments for Estimating Cost using Proportions

 Sep 08, 2013 Average Cost by: Staff Answer Part I Paul purchased 8 computers which cost him a total of \$6,016 cost of one computer = \$6016 / 8 computers cost of one computer = \$752 per computer Mary purchased 8 printers which cost her \$1,080. cost of one printer = \$1080 / 8 printers cost of one printer = \$135 per printer Steve purchased 25 DVD movies which cost \$350 cost of one DVD movie = \$350 / 25 DVD movies cost of one DVD movie = \$14 per DVD movie Sally purchased 34 CD’s which cost \$306. cost of one CD = \$306 / 34 CD’s cost of one CD = \$9 per CD -----------------------------------------------

 Sep 08, 2013 Average Cost by: Staff ----------------------------------------------- Part II How much would 3 computers, 4 printers, 15 DVD’s, and 18 CD’s cost ? Cost = (number of computers) * (cost of one computer) + (number of printers) * (cost of one printer) + (number of DVD’s) * (cost of one DVD) + (number of CD’s) * (cost of one CD) -----------------------------------------------

 Sep 08, 2013 Average Cost by: Staff ----------------------------------------------- Part III number of computers = 3 cost of a single computer = \$752 number of printers = 4 cost of a single computer = \$135 number of DVD’s = 15 cost of a single DVD = \$14 number of CD’s = 18 cost of a single CD = \$9 Cost = (3) * (\$752) + (4) * (\$135) + (15) * (\$14) + (18) * (\$9) Cost = 2256 + 540 + 210 + 162 Cost = \$3168 The final answer is: Cost = \$3168 -----------------------------------------------

 Sep 08, 2013 Average Cost by: Staff ----------------------------------------------- Part IV Thanks for writing. Staff www.solving-math-problems.com