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Factoring Trinomials of the type ax²+bx+c

by Torrey Jones
(Pricard, Alabama)










































Factor the following Trinomial

This process is the opposite of the FOIL method

I need help with this problem 2x squared + 3x + 1

Comments for Factoring Trinomials of the type ax²+bx+c

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Apr 04, 2012
Factor 2x² + 3x + 1
by: Staff

Question:

by Torrey Jones
(Pricard, Alabama)


I need help with this problem 2x squared+3x+1


Answer:

ax²+bx+c

= 2x² + 3x + 1

= (2x + 1)(x + 1)

>>> the final answer is: (2x + 1)(x + 1)

There are many ways to factor a trinomial. Here is one method:

Write two sets of parentheses to show the final factored form of the trinomial.

(         )(         )

The first term in the original expression is 2x². It is the product of the first term in the binomials.

(2x      )(x      )

The last term in the trinomial is 1. It is the product of the last terms of the binomials.

In this case, 1 can only equal 1*1 or (-1)*(-1).


There are only two possibilities:

(2x + 1)(x + 1) or (2x - 1)(x - 1)


(2x + 1)(x + 1) = 2x² + 3x + 1, correct

(2x - 1)(x - 1) = x² - 3x + 1, incorrect


The final answer is: (2x + 1)(x + 1)



Thanks for writing.

Staff
www.solving-math-problems.com


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