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Factoring trinomials











































factor

3y to the 2ed power + 14y + 8

Since the first term of the expanded expression begins with 3y^2,. . .

The factored form will look like this:

(3y + 1st number)(y + 2nd number)

Comments for Factoring trinomials

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Aug 17, 2010
Factoring Trinomial
by: Staff

The question:

3y to the 2ed power + 14y + 8

The answer:

3y^2 + 14y + 8



Note: since the first term of the expanded expression begins with 3y^2,
The factored form must look like this:

(3y + 1st number)(y + 2nd number)

I’m going to multiply these factors together to show you what choices are available for the 1st number and the 2nd number

(3y + 1st number)(y + 2nd number) = 3y^2 + (1st number)*y + (2nd number)*3y + (1st number)*(2nd number)

(1st number)*(2nd number) must = +8

(1st number) + (2nd number)*3 must = +14

The 1st number and the 2nd number must both be positive, because the both the middle term of the trinomial and the last term of the trinomial are both positive

Now we have

(3y + 1st positive number)(y + 2nd positive number)

The choice of the 1st positive number and the 2nd positive number is limited, since the product of the two numbers must = +8

The only choices are 8 x 1, or 2 x 4 – there are no other choices

You can try both combinations.

The final answer is:

(3y + 2)(y + 4)






Thanks for writing.


Staff
www.solving-math-problems.com



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