George and Sam sold 153 pairs of shoes

If George and Sam sold 153 pairs of shoes together but sam sold 19 less than george, how many did george sell?

Comments for George and Sam sold 153 pairs of shoes

 Feb 20, 2012 Word Problem by: Staff Question: If George and Sam sold 153 pairs of shoes together but sam sold 19 less than george, how many did george sell? Answer: George and Sam sold 153 pairs of shoes together George + Sam = 153 Sam sold 19 less than George Sam = George - 19 You now have two equations with two unknowns. 1st equation: George + Sam = 153 2nd equation: Sam = George - 19 Reformat the 2nd equation so that the variables Sam and George are on the left side of the equation. Sam = George - 19 Sam - George = George - George - 19 Sam - George = 0 - 19 Sam - George = 19 Reformat the 1st equation so that the variables Sam and George appear in the same order (this is not actually necessary, but it does make it easier to follow the solution). George + Sam = 153 Sam + George = 153 Add the reformatted versions of both equations: Sam + George = 153 Sam - George = 19 ------------------------ (Sam + Sam) + (George - George) = 153 - 19 2 * Sam + 0 = 134 2 * Sam = 134 Solve for Sam 2 * Sam = 134 2 * Sam / 2 = 134 / 2 Sam * (2 / 2) = 134 / 2 Sam * (1) = 134 / 2 Sam = 134 / 2 Sam = 67 (Sam sold 67 pairs of shoes) Solve for the number of shoes George sold using the 1st equation: George and Sam sold 153 pairs of shoes together George + Sam = 153 George + 67 = 153 George + 67 - 67 = 153 – 67 George + 0 = 153 - 67 George = 153 - 67 George = 86 (George sold 86 pairs of shoes) >>>the final answer is: George sold 86 pairs of shoes Sam sold 67 pairs of shoes Thanks for writing. Staff www.solving-math-problems.com