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George and Sam sold 153 pairs of shoes










































If George and Sam sold 153 pairs of shoes together but sam sold 19 less than george, how many did george sell?

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Feb 20, 2012
Word Problem
by: Staff



Question:

If George and Sam sold 153 pairs of shoes together but sam sold 19 less than george, how many did george sell?


Answer:

George and Sam sold 153 pairs of shoes together

George + Sam = 153


Sam sold 19 less than George

Sam = George - 19


You now have two equations with two unknowns.

1st equation: George + Sam = 153
2nd equation: Sam = George - 19


Reformat the 2nd equation so that the variables Sam and George are on the left side of the equation.

Sam = George - 19

Sam - George = George - George - 19

Sam - George = 0 - 19

Sam - George = 19


Reformat the 1st equation so that the variables Sam and George appear in the same order (this is not actually necessary, but it does make it easier to follow the solution).

George + Sam = 153

Sam + George = 153


Add the reformatted versions of both equations:

Sam + George = 153
Sam - George = 19
------------------------
(Sam + Sam) + (George - George) = 153 - 19

2 * Sam + 0 = 134

2 * Sam = 134


Solve for Sam

2 * Sam = 134

2 * Sam / 2 = 134 / 2

Sam * (2 / 2) = 134 / 2

Sam * (1) = 134 / 2

Sam = 134 / 2

Sam = 67 (Sam sold 67 pairs of shoes)


Solve for the number of shoes George sold using the 1st equation:

George and Sam sold 153 pairs of shoes together

George + Sam = 153

George + 67 = 153

George + 67 - 67 = 153 – 67

George + 0 = 153 - 67

George = 153 - 67

George = 86 (George sold 86 pairs of shoes)


>>>the final answer is:

George sold 86 pairs of shoes
Sam sold 67 pairs of shoes




Thanks for writing.

Staff
www.solving-math-problems.com



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