# Inverse Operations for Division Problems

If I have 35 divided by a = 7 and I use the inverse, why is it still dividing 35 by 7 and not multiplying 35 by 7? I know it should equal 5, but I want to know why the inverse method doesn't work.

### Comments for Inverse Operations for Division Problems

 Apr 19, 2012 Inverse Operations by: Staff Question: If I have 35 divided by a = 7 and I use the inverse, why is it still dividing 35 by 7 and not multiplying 35 by 7? I know it should equal 5, but I want to know why the inverse method doesn't work. Answer: Inverse Operations are important keys to checking computations in arithmetic. . . . because, an Inverse Operation gets you back to the number you started with. An inverse operation "undoes" an original action. It is the opposite of the original procedure. The inverse operation of addition is subtraction . The inverse operation of subtraction is addition. The inverse operation of multiplication is division . The inverse operation of division is multiplication. Your original problem is a division problem: 35 divided by 7 = 5 The "Inverse Operation" of multiplication will reverse the division, and return the number you started with: the number 35. 35 divided by 7 = 5 The inverse operation: 5 multiplied by 7 = 35 (the number you started with). Thanks for writing. Staff www.solving-math-problems.com