Logarithm
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Logarithm

(3.87^3+20)÷(3.87^3-20)

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Logarithm

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Aug 11, 2011
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Simplify Expression
by: Staff


The question:

(3.87^3+20)÷(3.87^3-20)


The answer:

(3.87^3+20)÷(3.87^3-20)

The notation is a bit unclear, but I think this is what you mean:

[3.87^(3+20)]÷[3.87^(3-20)]

= [3.87^(3+20)]/[3.87^(3-20)]

Since the base for both the numerator and denominator is the same

= 3.87^[(3+20)-(3-20)]

= 3.87^[(3-3)+(20+20)]

= 3.87^(0+40)

= 3.87^40

= 3.22432344197172E+23

The final answer is: 3.87^40, or 3.22432344197172E+23



log(3.87^40) = 40*log(3.87) = 23.5084386007565

10^(23.5084386007565) = 3.22432344197172E+23




Thanks for writing.

Staff
www.solving-math-problems.com

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