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Math - Age Word Problem

by Tracy Edwards











































1. Refer back to Week One Discussion and use the names and ages of yourself and the other two people you selected. Make sure one is older than you and one is younger than you.
2. In years, how old was the older person when you were born?
3. Write an equation that models how old in years each of you will be, when your ages add up to 150 years old. For example, if x = your age and the eldest person was a year older than you, you would write their age as x + 1. Then the equation would be: x + (x+1) = 150.
4. Explain the reasoning which helped you develop your equation.
5. Solve for your future ages. Are your answers reasonable, do they add up to 150?
6. In years, how old were you when the youngest person was born?
7. At some point during the lives of you and the youngest person, your age will be three times his/her age at that moment. Write an equation which models how old in years each of you will be when you are three times as old as the younger person.
8. Explain the reasoning which helped you develop your equation.
9. Solve the equation for your ages when you are three times as old as the youngest person. Are your answers reasonable?




Here is what i used for week one:


For this assignment I will be using my step daughter Nautica, my brother Earl and my Aunt Pat


Nautica (step daughter) 2: Factor: 2
Earl (brother), 27
27/3 = 9
9/3 = 3

Factors are 3, 3, 3

Aunt Pat, 50
50/2 = 25
25/5 = 5

Factors: 2, 5, 5

Comments for Math - Age Word Problem

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Aug 23, 2011
Age Word Problem
by: Staff

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Part II


3. Write an equation that models how old in years each of you will be, when your ages add up to 150 years old.

x + (x+14) = 150



4. Explain the reasoning which helped you develop your equation.

Your age + the age of someone 14 older than yourself = 150

x + (x + 14) = 150



5. Solve for your future ages. Are your answers reasonable, do they add up to 150?

x + (x + 14) = 150

(x + x) + 14 = 150

2x + 14 = 150

2x + 14 - 14 = 150 - 14

2x + 0 = 150 – 14

2x = 150 - 14

2x = 136

2x/2 = 136/2

x*(2/2) = 136/2

x*(1) = 136/2

x = 136/2

x = 68

when your age = 68
and Aunt Pat’s age = 68 + 14 = 82

then, the sum of your two ages will = 68 + 82 = 150


6. In years, how old were you when the youngest person was born?

Nautica (step daughter) 2 years old now

Your age now = Aunt Pat’s current age - Aunt Pat’s age when you were born

= 50 - 14

Your age now = 36

When Nautica (step daughter) was born, you were 36 - 2 = 34 years old





7. At some point during the lives of you and the youngest person, your age will be three times his/her age at that moment. Write an equation which models how old in years each of you will be when you are three times as old as the younger person.

x = your age
y = youngest person’s age

x = 3y

Since the youngest person (Nautica) was born when you were 34, she will always be 34 years younger than you will be:

y = x - 34

x = 3(x - 34)




8. Explain the reasoning which helped you develop your equation.

Since the youngest person (Nautica) was born when you were 34, she will always be 34 years younger than you will be.

y = x - 34

x = 3(x - 34)



9. Solve the equation for your ages when you are three times as old as the youngest person. Are your answers reasonable?

x = 3(x - 34)

x = 3*x - 3*34

x = 3x - 3*34

x = 3x - 102

x - x = 3x - x - 102

0 = 3x - x - 102

0 = 2x - 102

0 + 102 = 2x - 102 + 102

102 = 2x - 102 + 102

102 = 2x + 0

102 = 2x

102/2 = 2x/2

51= 2x/2

51= x*(2/2)

51= x*(1)

51= x

y = x - 34

y = 51 - 34

y = 17


When you are 51 years old, Nautica will be 17 years old (51-34=17).

When you are 51, your age will be exactly 3 times Nautica’s age:

3 * 17 = 51


Thanks for writing.

Staff
www.solving-math-problems.com



Aug 23, 2011
Age Word Problem
by: Staff


Part I

The question:

by Tracy Edwards

1. Refer back to Week One Discussion and use the names and ages of yourself and the other two people you selected. Make sure one is older than you and one is younger than you.

2. In years, how old was the older person when you were born?

3. Write an equation that models how old in years each of you will be, when your ages add up to 150 years old. For example, if x = your age and the eldest person was a year older than you, you would write their age as x + 1. Then the equation would be: x + (x+1) = 150.

4. Explain the reasoning which helped you develop your equation.

5. Solve for your future ages. Are your answers reasonable, do they add up to 150?

6. In years, how old were you when the youngest person was born?

7. At some point during the lives of you and the youngest person, your age will be three times his/her age at that moment. Write an equation which models how old in years each of you will be when you are three times as old as the younger person.

8. Explain the reasoning which helped you develop your equation.

9. Solve the equation for your ages when you are three times as old as the youngest person. Are your answers reasonable?




Here is what i used for week one:


For this assignment I will be using my step daughter Nautica, my brother Earl and my Aunt Pat


Nautica (step daughter) 2: Factor: 2
Earl (brother), 27
27/3 = 9
9/3 = 3

Factors are 3, 3, 3

Aunt Pat, 50
50/2 = 25
25/5 = 5

Factors: 2, 5, 5


The answer:

1. Refer back to Week One Discussion and use the names and ages of yourself and the other two people you selected. Make sure one is older than you and one is younger than you.


For this assignment I will be using my step daughter Nautica, my brother Earl and my Aunt Pat

Nautica (step daughter) 2: Factor: 2
Earl (brother), 27
27/3 = 9
9/3 = 3

Factors are 3, 3, 3

Aunt Pat, 50
50/2 = 25
25/5 = 5

Factors: 2, 5, 5



2. In years, how old was the older person when you were born?

This INFORMATION is NECESSARY to complete the problem.

Since it was NOT INCLUDED with the statement of the problem, I am going to ASSUME the following:

The older person (Aunt Pat) was 14 years old when you were born. (You can replace the 14 I used in the equations with the correct age at a later time).

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