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Math Problems - Percent











































Can you Help me solve math problem for my 6th grade brother. question is-
1. At Rober's school, 40% of the 70 sixth-grade wear eitehr glasses or contact lenses.
How many sixth grader students wear either glasses or contact lenses?
There are 7 studnets who wear glasses. Of the students who wear glasses or contact lense, what percent of students wear glasses? show work.

2. Maria has a jar of 80 M&M's. She has 16 red, 12 blue, 18 green and 34 yellow.
a. what percent of the time would you expect to randomly choose a red M&M.
b. Maria's brother, Teddy snuck into her room and ate all of her green M&M's and 7 yellow M&M's. Now what's the probability of selecting blue M&M? (write as fraction)

Comments for Math Problems - Percent

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May 11, 2011
Math Problems - Percent
by: Staff

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Part II

2. Maria has a jar of 80 M&M's. She has 16 red, 12 blue, 18 green and 34 yellow.

a. what percent of the time would you expect to randomly choose a red M&M?

red = (number of red)/(total number of M&M’s)

red = (16)/(80)

red = 2/10

red = 0.2

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To convert the 0.2 to a percent, multiply by 100

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red = (0.2)*100

red = 20% (20% of the total number of M&M’s are red)

The percent of the time would you expect to randomly choose a red M&M is also 20%.



b. Maria's brother, Teddy snuck into her room and ate all of her green M&M's and 7 yellow M&M's. Now what's the probability of selecting blue M&M? (write as fraction)


blue = (number of blue)/(total number of M&M’s which were not eaten)

total number of M&M’s which were not eaten = 80 - 18 green eaten – 7 yellow eaten

total number of M&M’s which were not eaten = 55 not eaten

blue = (12 blue)/(55 not eaten)

blue = (12 blue)/(55 not eaten)

blue = 12/55

The probability of randomly choosing a blue M&M is also 12/55.



The final answers:


Problem 1

28 students wear glasses or contact lenses

25% wear glasses (25% of the total number students who wear glasses or contact lenses)


Problem 2

The percent of the time would you expect to randomly choose a red M&M is 20%.

The probability of randomly choosing a blue M&M is 12/55.




Thanks for writing.

Staff
www.solving-math-problems.com



May 11, 2011
Math Problems - Percent
by: Staff


Part I

The question:

Can you Help me solve math problem for my 6th grade brother. question is-

1. At Rober's school, 40% of the 70 sixth-grade wear eitehr glasses or contact lenses.
How many sixth grader students wear either glasses or contact lenses?

There are 7 studnets who wear glasses. Of the students who wear glasses or contact lense, what percent of students wear glasses? show work.

2. Maria has a jar of 80 M&M's. She has 16 red, 12 blue, 18 green and 34 yellow.

a. what percent of the time would you expect to randomly choose a red M&M?

b. Maria's brother, Teddy snuck into her room and ate all of her green M&M's and 7 yellow M&M's. Now what's the probability of selecting blue M&M? (write as fraction)

The answer:

1. At Rober's school, 40% of the 70 sixth-grade wear either glasses or contact lenses.

How many sixth grader students wear either glasses or contact lenses?

How many = (total number of students) * (percent)

How many = (70 students) * (40%)

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Before multiplying, you must change the 40% into a fraction or a decimal

Changing 40% into a fraction (the % sign means divide by 100)

40% = 40÷100

40% = 40/100

40% = 4/10

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How many = (70 students) * (4/10)

How many = (70*4)/10

How many = (280)/10

How many = 28 students wear glasses or contact lenses



There are 7 students who wear glasses. Of the students who wear glasses or contact lenses, what percent of students wear glasses? Show work.


students = (number who wear glasses)/(total number who wear glasses & contacts)

students = (7)/(28)

students = 1/4

students = 0.25

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To convert the 0.25 to a percent, multiply by 100

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students = (0.25)*100

students = 25% wear glasses (25% of the total number students who wear glasses or contact lenses)
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