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Math question - Prime Numbers

by Lisa
(NJ)











































generate a equation using at least five numbers; 0 (zero), two even, and two odd to get a prime number. For example; (a) x = 0 => x2 – x + 41 = 0 – 0 + 41 = 41, which is prime. (b) Two even:

x = 2 => x2 – x + 41 = 22 – 2 + 41 = 4 – 2 + 41 = 43, which is prime. x = 4 =>

x2 – x + 41 = 42 – 4 + 41 = 16 – 4 + 41 = 53, which is prime. (c) Two odd: x = 1 =>

x2 – x + 41 = 12 – 1 + 41 = 1 – 1 + 41 = 41, which is prime. x = 3 => x2 – x + 41 =

9 – 3 + 41 = 6 + 41 = 47, which is prime.



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May 22, 2011
Prime Number Equation
by: Staff


The question:

by Lisa
(NJ)

generate a equation using at least five numbers; 0 (zero), two even, and two odd to get a prime number. For example; (a) x = 0 => x2 – x + 41 = 0 – 0 + 41 = 41, which is prime. (b) Two even:

x = 2 => x2 – x + 41 = 22 – 2 + 41 = 4 – 2 + 41 = 43, which is prime. x = 4 =>

x2 – x + 41 = 42 – 4 + 41 = 16 – 4 + 41 = 53, which is prime. (c) Two odd: x = 1 =>

x2 – x + 41 = 12 – 1 + 41 = 1 – 1 + 41 = 41, which is prime. x = 3 => x2 – x + 41 =

9 – 3 + 41 = 6 + 41 = 47, which is prime.



The answer:


(a) x = 0

=> x + 2 = 0 + 2 = 2, which is prime.


(b) Two even:


x = 4

=> sqrt(x) + 9 = sqrt(4) + 9 = 2 + 9 = 11, which is prime.


x = 64

=> x^(1/3) - 1 = 64^(1/3) - 1 = 4 - 1 = 3, which is prime.


(c) Two odd:


x = 13

=>39/x = 39/13 = 3, which is prime


x = 7

=>3(x + 5) + 5 = 3(7 + 5) + 5 = 3*12 + 5 = 36 + 5 = 41, which is prime




Thanks for writing.

Staff
www.solving-math-problems.com



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