logo for solving-math-problems.com
leftimage for solving-math-problems.com

Math - Weight, of the heavier of 2 packages

by Renee
(Ashland)











































The difference between the weights of two packages is 12 ounces,and the mean of the weights is 78 ounces. What is the weight,in ounces,of the heavier of the 2 packages?

Comments for Math - Weight, of the heavier of 2 packages

Click here to add your own comments

Jun 19, 2012
Weight of the heavier of 2 packages
by: Staff


The answer:

x = weight of 1st package, the heavier package

y = weight of 2nd package



The difference between the weights of two packages is 12 ounces

x - y = 12


the mean (or average) of the weights is 78 ounces

(x + y) / 2 = 78



You now have two equations with two unknowns

x - y = 12

(x + y) / 2 = 78


Solve for x in the 1st equation

x - y = 12

x - y + y = 12 + y

x + 0 = 12 + y

x = 12 + y


Substitute 12 + y for x in the 2nd equation

(x + y) / 2 = 78

(12 + y + y) / 2 = 78


Solve for y

(12 + y + y) / 2 = 78

(12 + 2y) / 2 = 78

(12 / 2) + (2y) / 2 = 78


6 + y = 78

6 - 6 + y = 78 - 6

0 + y = 78 - 6

y = 72


Substitute 72 for y in the 1st equation


x = 12 + y

x = 12 + 72

x = 84




>>> the final answer is:


x = weight of 1st package, the heavier package = 84 ounces

y = weight of 2nd package = 72 ounces


-------------------------------------

check the answer:



The difference between the weights of two packages is 12 ounces

x - y = 12

84 - 72 = 12

12 = 12, OK


the mean (or average) of the weights is 78 ounces

(x + y) / 2 = 78

(84 + 72) / 2 = 78

(156) / 2 = 78

78 = 78, OK





Thanks for writing.

Staff
www.solving-math-problems.com



Sep 18, 2013
Math for dummies
by: Ned

Thank a million for your help.I am browsing the internet and just happen to come up to this site,Is there a email address so I may be able to go on your site directly.

thanks again

Click here to add your own comments

Join in and write your own page! It's easy to do. How? Simply click here to return to Math Questions & Comments - 01.



Copyright © 2008-2015. All rights reserved. Solving-Math-Problems.com