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Mathematics in Our World page 331 - Equation











































i need help in solving this two equation step by step x2-2x-3 and x2+12-64 thank you very much

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Jun 05, 2011
Solve Equations
by: Staff


The question:

i need help in solving this two equation step by step x2-2x-3 and x2+12-64 thank you very much


The answer:

Problem 1

x² - 2x - 3 = 0

this problem can be solved easily by factoring the expression x² - 2x - 3

by factoring

x² - 2x - 3 = 0

(x - 3)*(x + 1) = 0

(x – 3) = 0

x – 3 = 0

x – 3 + 3 = 0 + 3

x + 0 = 0 + 3

x = 0 + 3

x = 3


(x + 1) = 0

x + 1 = 0

x + 1 - 1 = 0 - 1

x + 0 = 0 - 1

x = 0 – 1

x = - 1



the final solution to x² - 2x - 3 = 0: x = -1, x = 3


check the solution by substituting the values of x into the original equation:

for x = -1

x² - 2x - 3 = 0

(-1)² - (2)*(-1) - 3 = 0

1 + 2 - 3 = 0

3 - 3 = 0

0 = 0, OK


for x = 3

x² - 2x - 3 = 0

(3)² - (2)*(3) - 3 = 0

9 - 6 - 3 = 0

3 - 3 = 0

0 = 0, OK





Problem 2

x² + 12x - 64 = 0

this problem can be solved easily by factoring the expression x² + 12x - 64

by factoring

x² + 12x - 64 = 0

(x - 4)*(x + 16) = 0


(x - 4) = 0

x - 4 = 0

x - 4 + 4 = 0 + 4

x + 0 = 0 + 4

x = 0 + 4

x = 4


(x + 16) = 0

x + 16 = 0

x + 16 - 16 = 0 - 16

x + 0 = 0 - 16
x = 0 - 16

x = -16



the final solution to x² + 12x - 64 = 0: x = -16, x = 4


check the solution by substituting the values of x into the original equation:

for x = -16

x² + 12x - 64 = 0

(-16)² + (12)*(-16) - 64 = 0

256 - 192 - 64 = 0

64 - 64 = 0

0 = 0, OK


for x = 4

x² + 12x - 64 = 0

(4)² + (12)*(4) - 64 = 0

16 + 48 - 64 = 0

64 - 64 = 0

0 = 0, OK






Thanks for writing.

Staff
www.solving-math-problems.com


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