# more pupils in school A than School B

by judy

There are more pupils in schl A than Schl B. 30% of the pupils in schl A is 45 more than 40% ofthe pupils in schl B. If 10% of the pupils in school A leaves to join schl B,there will be 200 more pupils in schl A than schl B.
How many pupils are there in schl B.
How many percent less pupils are there in schl B than in schl A. Leave your answer as fraction in the simplest form.

Julian had 300 more cards than faizal. Julian gave 3/5 of his cards to faizal. Faizal then gave 1/4 of the total number of what he had then to Julian. In the end Faizal had 300 more cards than julian. How many cards did Julian have at first?

A basketball is thrown from a height of 20 metres. after each bounce, it only reaches half the height of the previous bounce. when the ball touches the gound for the third time, how much vertical distance has it moved.

### Comments for more pupils in school A than School B

 Jan 06, 2011 Math - Word Problem 1 by: Staff The question: by Judy Problem 1: There are more pupils in schl A than Schl B. 30% of the pupils in schl A is 45 more than 40% ofthe pupils in schl B. If 10% of the pupils in school A leaves to join schl B,there will be 200 more pupils in schl A than schl B. How many pupils are there in schl B. How many percent less pupils are there in schl B than in schl A. Leave your answer as fraction in the simplest form. The answer: (Since I only have a maximum of 3000 characters I can use, I must eliminate about half of the detailed steps.The most important part of this problem is setting up the two equations, so I have tried to keep the most detail there.) This problem can be solved by writing two equations. Each equation will have two unknowns. Defining the unknowns: X = number of students in school A Y = number of students in school B Write the two equations. Write down each sentence from the statement of the problem . . . one at a time. Convert each sentence to a mathematical statement (in this case, an equation): The first equation: 30% of the pupils in schl A is 45 more than 40% of the pupils in schl B. (30% times the number of students in school A = 40% of the number of students in school B + another 45% of the 40%) 30% * X = 40% * Y + 45 Convert the percents to their decimal equivalents (divide the % by 100): .3 * X = .4 * Y + 45 The second equation: If 10% of the pupils in school A leaves to join schl B (which will add 10% * X pupils to school B), there will be 200 more pupils in schl A than schl B. X - 10% * X = Y + 10% * X + 200 Convert the percents to their decimal equivalents (divide the % by 100): X - .1 * X = Y + .1 * X + 200 We now have two equations with two unknowns. This is just what we need to solve the problem. .3 * X = .4 * Y + 45 X - .1 * X = Y + .1 * X + 200 Now it’s just a matter of solving the two equations for X & Y 1st equation – no further simplification is necessary .3 * X = .4 * Y + 45 2nd equation – simplify .8 * X = Y + 200 The final (simplified) versions of equations 1 & 2 are: .3 * X = .4 * Y + 45 .8 * X = Y + 200 I am going to solve for X using the addition/subtraction method. To begin, multiply equation two by .4 (each side of the equation). This will transform the Y on the right hand side of the equation to .4 * Y (which is what I need when I subtract the two equations). Next, multiply the second equation by -1. Solving for X by subtracting the two equations: X = 1750, school A has 1750 pupils Now, solve for the number of students in school B. Substitute the 1750 for X in either of the two original equations, then solve for Y. Y = 1200, school B has 1200 pupils Calculate how many % less pupils school B has when compared to school A % = [(1750 – 1200)/1750] * 100 % = 31.43 The final answer, part 1: School A has 1750 pupils. School B has 1200 pupils. School B has 31.43% fewer students than School A. Thanks for writing. Staff www.solving-math-problems.com