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Solving for variables

by Gold
(PA)











































Given

h = at - .25vt^2

Solve for the variable "a" using algebra.

Different kinds of equations do require different techniques to solve them.

In this case, use "PEMDAS in reverse" to isolate the variable "a".

Comments for Solving for variables

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Oct 29, 2011
Solving for Variables
by: Staff


Question:

by Gold
(PA)



h=at-.25vt^2 Solve for a.



Answer:

h = at - .25vt²


add .25vt² to each side of the equation

h + .25vt² = at - .25vt² + .25vt²

h + .25vt² = at + 0

h + .25vt² = at


divide each side of the equation by t

(h + .25vt²) / t = at / t

(h + .25vt²) / t = a * (t / t)

(h + .25vt²) / t = a * (1)

(h + .25vt²) / t = a


The final answer is:

a = (h + .25vt²) / t


There may be a mistake in the equation. I don’t remember seeing a physics problem involving height and acceleration which used an equation that looked quite like this.



Thanks for writing.

Staff
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