# Time and Work Equations

by Ashish
(Ranchi,Jharkhand,India)

a certai job was assigned to a group of men to do in 20 days. but 12 men did not turn up for the job and the remaning men did the job in32 days.the original number of men in the group was?

### Comments for Time and Work Equations

 Jul 09, 2011 Time and Work Equations by: Staff The question: a certai job was assigned to a group of men to do in 20 days. but 12 men did not turn up for the job and the remaning men did the job in 32 days.the original number of men in the group was? The answer: x = number of men in the original group The total number of man-days required to complete the job will not change, regardless of the number of men working on the job. man-days for partial crew to complete job = man-days for assigned crew (original group) set up equation (x men - 12 men) * (32 days) = (x men) * (20 days) (x - 12) * (32) = (x) * (20) Solve for x Eliminate the parentheses on the left side of the equation using the distributive law 32*x - 32*12 = x*20 32x - 384 = 20x Add 384 to each side of the equation to eliminate the 384 from the left side of the equation 32x - 384 + 384 = 20x + 384 32x + 0 = 20x + 384 32x = 20x + 384 Subtract 20x from each side of the equation to eliminate the 20x from the right side of the equation 32x - 20x = 20x - 20x + 384 12x = 20x - 20x + 384 12x = 0 + 384 Divide each side of the equation by 12 to eliminate the 12 on the left side of the equation. 12x = 384 12x/12 = 384/12 12x/12 = 32 x*(12/12) = 32 x*(1) = 32 x = 32 the final answer is: the size of the original group was 32 men Thanks for writing. Staff www.solving-math-problems.com