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Word Problem - 3 Way Split - Math Question










































between the three they have 100.00. molly has 3 times as much as simon and carlos has 2 times as much as molly. how much does simon have and how much does carlos have?

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Mar 29, 2012
Word Problem - 3 Way Split
by: Staff


Answer:


Total = Molly + Simon + Carlos = 100

Molly = 3*(Simon)

Carlos = 2*(Molly)


Molly + Simon + Carlos = 100

Molly + Simon + 2*(Molly)= 100

3*(Simon)+ Simon + 2*(3*(Simon))= 100


Solve for Simon

3*(Simon) + Simon + 2*[3*(Simon)] = 100

3*(Simon) + Simon + 6*(Simon) = 100

10*(Simon) = 100

10*(Simon) / 10 = 100 / 10

(Simon) * (10 / 10) = 100 / 10

(Simon) * (1) = 100 / 10

Simon = 100 / 10

Simon = 10


Solve for Molly

Molly = 3*(Simon)

Molly = 3*(10)

Molly = 30


Solve for Carlos

Carlos = 2*(Molly)

Carlos = 2*(30)

Carlos = 60


Check TOTAL

Total = Molly + Simon + Carlos = 100


100 = Molly + Simon + Carlos

100 = 30 + 10 + 60

100 = 100


>>> final answer:

Simon = 10
Carlos = 60
Molly = 30





Thanks for writing.

Staff
www.solving-math-problems.com


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