# y = 3x + 7 - Algerbra 1

A line has equation y = 3x + 7 and pass through point(h,h + 15). Find the value of h.

### Comments for y = 3x + 7 - Algerbra 1

 Apr 17, 2012 y = 3x + 7 by: Staff Question: A line has equation y = 3x + 7 and pass through point (h, h + 15). Find the value of h. Answer: y = 3x + 7 The line representing the equation passes through the data point (h, h + 15). This mean that x = h and y = h + 15 at that point. Because of this equivalence, you can substitute “h” for x in the equation, and “h + 15” for y in the equation. y = 3x + 7 h + 15 = 3h + 7 Now you can solve for “h” directly Subtract h from each side of the equation h + 15 - h = 3h + 7 - h h - h + 15 = 3h - h + 7 0 + 15 = 3h - h + 7 15 = 3h - h + 7 15 = 2h + 7 Subtract 7 from each side of the equation 15 - 7 = 2h + 7 - 7 15 - 7 = 2h + 0 15 - 7 = 2h 8 = 2h Divide each side of the equation by 2 2h = 8 2h/2 = 8/2 h*(2/2) = 8/2 h*(1) = 8/2 h = 8/2 h = 4 >>> the final answer: h = 4 Check the answer y = 3x + 7 if x = h and y = h + 15 h + 15 = 3h + 7 if h = 4 4 + 15 = 3*4 + 7 19 = 19, OK → h = 4 is a VALID solution. Thanks for writing. Staff www.solving-math-problems.com